Question

sum of 3 terms of which one is AP is 21 . and then product is 21 . Find the terms.​

Answer 1

Answer:

Here is ur answer

Step-by-step explanation:

Now,

Now,a(a+2d)-(a+d) = 6

a{a+2(7-a)}-7 = 6

a{a+14-2a}=13

a{14-a} =13

14a-a^2 =13

a^2 -14a +13 = 0

By applying quadratic formula, you will get

By applying quadratic formula, you will geta= 13, 1.

d will be 7-a i.e. -6 ,6.

Now, there will be two AP

Now, there will be two AP13,7, 1 and 1,7,13.

Answer 2

Step-by-step explanation:

Let the three terms of A.P are a,a+d,a+2d.

Now,As per the question , 

a+a+d+a+2d=3a+3d=21

 i.e. a+d=7 or, d=7−a.

Now,a(a+2d)−(a+d)=6

a{a+2(7−a)}−7=6

a{a+14−2a}=13

a{14−a}=13

14a−a2=13

a2−14a+13=0

By factorising,we get

a=13,1

d=7−a 

For a=13,1d=7−13,7−1=−6,6 respectively.

Now, there are two AP's a,a+d,a+2d for two values of a and d

13,7,1  and 1,7,13