sum of 30 terms of a series in AP whose last term is 98 is 1635 find the first term and the common difference
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a+29d=98 -equation1
sum of 30 terms is 1635
30/2 (2a+29d)=1635
put value of a+29d
15*(a+98)=1635
a=11
so d is 3
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sum of 30 terms is 1635
30/2 (2a+29d)=1635
put value of a+29d
15*(a+98)=1635
a=11
so d is 3
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become my followers
please
it will help you
vish5102004:
thenwhat is answer
first term is 11 and common difference is 3
then solve it
then solve it
ok
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Answered by
15
here the first term is 11 and the difference is 3
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