Question

sum of (3p^2+q^2)and(2q^2-p^2)​

Answer 1

Answer:

Suppose (a+b) and (c−d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a+b)×(c−d)=a×(c−d)+b×(c−d)=(a×c−a×d)+(b×c−b×d)

=ac−ad+bc−bd

Let,

a=3p2,b=q2,c=2p2,d=3q2

Now, 

=3p2×(2p2−3q2)+q2×(2p2−3q2)

=[(3p2×2p2)+(3p2×−3q2)]+[(q2×2p2)+(q2×−3q2)]

=[6p4−9p2q2+2q2p2−3q4)]

=[6p