Question

sum of 4 consecutive integers is 266 what are these integers

Answer 1

let the first integer be x
so 2nd is x + 1
3rd is x + 2
and 4rth is x + 3
thus x + x +1 +x +2 +x +3 =266
4 x = 266 - 6 = 260
x = 65
so the four consecutive integers are 65 , 66 , 67 and 68 .

Answer 2

Heya !!

Here is your Answer.

Given that Sum of 4 consecutive integers is 266.

Let the first integer be x.
2nd Integer = x + 1
3rd Integer = x + 2
4th integer = x + 3

ATQ,
x + (x + 1) + (x + 2) + (x + 3) = 266
4x + 6 = 266
4x = 260
x = 65

Hence, next integers are ...
x + 1 = 66
x + 2 = 67, and
x + 3 = 68.

Hope You Got It