Question

Sum of 4 consecutive no is 350 what is the sum of squares of largest no and smallest no

Answer 1

Let the numbers be X,(X+1),(X+2) and (X+3) respectively.

A/Q:-

X+(X+1)+(X+2)+(X+3)=350

=> X+X+1+X+2+X+3=350

=> 4x+6=350

=> 4x=350-6

=344

∴ X=344÷4

=86

1st consecutive no.=X=86

2nd consecutive no.=(X+1)=86+1=87

3rd consecutive no.=(X+2)=86+2=88

4th consecutive no.=(X+3)=86+3=89

Now,

The largest consecutive no. we got=89

The smallest consecutive no. we got=86

The sum of squares of these two numbers=(89)^2+(86)^2

=7921+7396

=15,317

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