Question

sum of 4 consecutive terms which are in ap is 32 and the ratio of the product of the first and last term to the product of 2 middle terms is 7:15 find the numbers​

Answer 1

(a – 3d) + (a – d) + (a + d) + (a + 3d) = 32 4a = 32  a = 8 ...(i)  and, according to the 2nd condition given, Numbers are 2, 6, 10 and 14 or 14, 10, 6 and 2.Read more on Sarthaks.com - https://www.sarthaks.com/651349/sum-four-consecutive-numbers-ratio-product-the-first-and-last-terms-product-middle-terms