Sum of 4 numbers is an Ap is 86 and sum of their squares is 1894.Find the numbers
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0
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Step-by-step explanation:
Answered by
2
Answer:
17 , 20 , 23 , 26
Step-by-step explanation:
Let say 4 number are
a - 3d , a - d , a+ d , a + 3d
then Sum
=> a - 3d + a - d + a + d + a + 2d = 86
=> 4a = 86
=> a = 43/2
=> a = 21.5
Sum of Squares = 1894
(a - 3d)² + (a - d)² + (a + d)² + (a + 3d)² = 1894
=> a² + 9d² - 6d + a² + d² - 2d + a² + d² + 2d + a² + 9d² + 6d = 1894
=> 4a² + 20d² = 1894
=> a² + 5d² = 473.5
=> (21.5)² + 5d² = 473.5
=> 5d² = 11.25
=> d² = 2.25
=> d = 1.5
So numbers are
21.5 - 3*1.5 , 21.5 - 1.5 , 21.5 + 1.5 , 21.5 + 3*1.5
=> 17 , 20 , 23 , 26
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