Question

Sum of 5 consecutive terms in an AP is 55.Difference of first and last terms is 60.Then find the terms

Answer 1

Answer: -19, -4, 11, 26, 41

Step-by-step explanation:

Sum of 5 consecutive terms = 5 x middle term

∴ middle term = 11

the terms are 11-2d, 11-d, 11, 11+d, 11+2d

Difference between first and last term is 60

(11+2d)-(11-2d)=60

4d = 60

d = 15

Then terms are -19, -4, 11, 26, 41

Answer 2

Let the numbers be a-2d, a-d,a,a+d,a+2d. Now. According to the question...................................a-2d+ a-d+a+ a+d+a+2d=55
5a=55
a=11
Next ,a-2d-(a+2d)=60
a-2d-a-2d=60
-4d =60
d=-15


a-2d= 11-2(-15)=41
a-d=11-(-15)=26
a =11
a+d= 11+(-15)=-4
a+2d =11+2(-15)=-19.

App is 41,26,11,-4,-19 ..