sum of 6 consecutive odd numbers is 168.find the largest of these numbers
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we have given that :
Sum of 6 consecutive odd numbers is 168.
we have to find :
Largest number =?
solution:-
because these are consecutive odd numbers.
let;
1st number = x
2nd number = (x+2)
3rd number = (x+4)
4th number = (x+6)
5th number = (x+8)
6th number = (x+10)
According to question :-
x + (x + 2)+ (x+4)+ (x+6)+(x+8) +(x+10) = 168
=> 6x + 30 = 168
=> 6x = 168 - 30 = 138
=> x = 23
Hence;
1st number = x = 23
2nd number = (x+2) = 23 + 2 = 25
3rd number = (x+4) = 23 + 4 = 27
4th number = (x+6) = 23 + 6 = 29
5th number = (x+8) = 23 + 8 = 31
6th number = (x+10) = 23 + 10 = 33 Answer
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✪✪ hope it helps ✪✪
//////////////////////////////////////////////////////////////////
we have given that :
Sum of 6 consecutive odd numbers is 168.
we have to find :
Largest number =?
solution:-
because these are consecutive odd numbers.
let;
1st number = x
2nd number = (x+2)
3rd number = (x+4)
4th number = (x+6)
5th number = (x+8)
6th number = (x+10)
According to question :-
x + (x + 2)+ (x+4)+ (x+6)+(x+8) +(x+10) = 168
=> 6x + 30 = 168
=> 6x = 168 - 30 = 138
=> x = 23
Hence;
1st number = x = 23
2nd number = (x+2) = 23 + 2 = 25
3rd number = (x+4) = 23 + 4 = 27
4th number = (x+6) = 23 + 6 = 29
5th number = (x+8) = 23 + 8 = 31
6th number = (x+10) = 23 + 10 = 33 Answer
////////////////////////////////////////////////////////////////////////////////////////////////////
✪✪ hope it helps ✪✪
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