Sum of 6 terms of an ap is zero and 4th term is 2 find the sum of 30 terms
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Answer:
Step-by-step explanation:
S6=0
a4=2
S30=?
So, a4=a+3d
2=a+3d
(a+3d=2)*2——> 2a+6d=4
S6=0
6/2[2a+5d]=0
2a+5d=0 ————-(2)
From (1) and (2),
2a+5d=0
2a+6d=4
(-) (-) (-)
———————
-1d=-4
d=4
2a+5d=0
2a+20=0
a=-10
Now,
S30= 15[2a+29d]
= 15(-20+116)
= 15*96
=1440
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