sum of 71+72+73+ ..... 100
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let that sum be s₇₁-₁₀₀
s₁₋₇₀+s₇₁-₁₀₀=s₁-₁₀₀
s₁₋ₓ=x(x+1)/2
so s₇₁-₁₀₀= s₁-₁₀₀ - s₁-₇₀ =100*101/2 - 70*71/2 =2565
s₁₋₇₀+s₇₁-₁₀₀=s₁-₁₀₀
s₁₋ₓ=x(x+1)/2
so s₇₁-₁₀₀= s₁-₁₀₀ - s₁-₇₀ =100*101/2 - 70*71/2 =2565
kinkyMkye:
Thanks!
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