Question

sum of 8 consecutive no.s, each number having difference 3 is 172. What are the 8 no.s ?​

Answer 1

Answer:

let the first no. be - x

the other no.s will be

x ,x+3 ,x+6 , x+9 ,x+12 ,x+15 ,x+18 and x+21

x+(x+3)+(x+6)+(x+9)+(x+12)+(x+15)+(x+18)+(x+21) = 172

8x + 84 = 172

8x = 172-84

8x = 88

x = 88/8

x = 11

Now , the numbers are

11 ,14 ,17 ,20 ,23 ,26 ,29 ,32 ( These are the numbers obtained by adding 3 to each number )

x = 11

x+3 = 14

x+6 = 17

x+9 = 20

x+12 = 23

x+15 = 26

x+18 = 29

x+21 = 32

Now their sum will be 172