Question

sum of 8terms of an AP is 136 and that of 15terms of an AP is 465 find the sum of first 25 terms?​

Answer 1

Answer:

808

Step-by-step explanation:

t1= 8, t2= 15, t3= 25

AP= 136

AP=465

tn=(a+(n-1)d)

t49=(8+(49-1)-25)

t49=(8+(48)-25)

t49=(56-25)

t49=(27)

AP= 136+ 465

= 601

tn= 601 + 27

= 808