sum of (a+3b-4c)+(4a-b+9c)+(-2b+3c-a)
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Answered by
11
Heya,
Ur answer is here.
(a + 3b - 4c) + (4a - b + 9c) + (-2b + 3c-a)
Lets open the brackets,
a + 3b - 4c + 4a - b + 9c - 2b + 3c -a
= 4a + 8c
Now, taking 4 as common, we get a + 2c.
Hence, the answer is a + 2c.
hope it helps
Ur answer is here.
(a + 3b - 4c) + (4a - b + 9c) + (-2b + 3c-a)
Lets open the brackets,
a + 3b - 4c + 4a - b + 9c - 2b + 3c -a
= 4a + 8c
Now, taking 4 as common, we get a + 2c.
Hence, the answer is a + 2c.
hope it helps
Answered by
10
Given Equation is (a + 3b - 4c) + (4a - b + 9c) + (-2b + 3c - a)
= a + 3b - 4c + 4a - b + 9c + (-2b + 3c - a)
= a + 3b - 4c + 4a - b + 9c - 2b + 3c - a
= a + 4a - a + 3b - b - 2b - 4c + 9c + 3c
= 4a + 3b - b - 2b - 4c + 9c + 3c
= 4a - 4c + 9c + 3c
= 4a + 5c + 3c
= 4a + 8c.
Hope this helps!
= a + 3b - 4c + 4a - b + 9c + (-2b + 3c - a)
= a + 3b - 4c + 4a - b + 9c - 2b + 3c - a
= a + 4a - a + 3b - b - 2b - 4c + 9c + 3c
= 4a + 3b - b - 2b - 4c + 9c + 3c
= 4a - 4c + 9c + 3c
= 4a + 5c + 3c
= 4a + 8c.
Hope this helps!
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