Math, asked by agnik, 1 year ago

sum of (a+3b-4c)+(4a-b+9c)+(-2b+3c-a)

Answers

Answered by RehanAhmadXLX
11
Heya,

Ur answer is here.

(a + 3b - 4c) + (4a - b + 9c) + (-2b + 3c-a)

Lets open the brackets,

a + 3b - 4c + 4a - b + 9c - 2b + 3c -a
= 4a + 8c 
Now, taking 4 as common, we get a + 2c.


Hence, the answer is a + 2c.

hope it helps
Answered by siddhartharao77
10
Given Equation is (a + 3b - 4c) + (4a - b + 9c) + (-2b + 3c - a)


= a + 3b - 4c + 4a - b + 9c + (-2b + 3c - a)

= a + 3b - 4c + 4a - b + 9c - 2b + 3c - a

= a + 4a - a + 3b - b - 2b - 4c + 9c + 3c

= 4a + 3b - b - 2b - 4c + 9c + 3c

= 4a - 4c + 9c + 3c

= 4a + 5c + 3c

 = 4a + 8c.


Hope this helps!
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