Question

sum of a digit of a two digit number is 9 if 27 is added to the number the digit get interchanged find the number​

Answer 1

Answer:

hiii

your answer is here !

Step-by-step explanation:

let the number be xy

x+y=9...............(1)

(10x+y)+27=10y+x

10x-x+y-10y=-27

9x-9y=-27

x-y=-3................(2)

add equation 1 and 2

we get

x=3

substitute it in eq 1

y=6

so the number is 36

$follow \: \: \: \: me$

Answer 2

Let the digit at unit place and ten's place be y and x respectively.

According to the question:

==> sum of digits = 9

==> x + y = 9 ...(1)

Also,

==> Original number + 27 = number with digits interchanged

==> 10x + y + 27 = 10y + x

==> 10x - x + y - 10y = -27

==> 9x - 9y = -27

==> x - y = -3 ...(2)

Adding (1) and (2)

==> x + y + x - y = 9 - 3

==> 2x = 6

==> x = 3

Putting x = 3 in (1)

==> x + y = 9

==> y = 9 - x

==> y = 9 - 3

==> y = 6

Number = 10x + y

==> 10(3) + 6

==> 30 + 6

==> 36

Hence, The number is 36