Question

sum of a digit of a two digit number is 9 when we interchange the digits if we found that the resulting new number is greater than the original number by 27 what is the two digit number ​

Answer 1

Answer:

63 and 36 is the required answer

Answer 2

Let the unit digit be b and tens digit be a.

ATP,

Number formed= 10a+b

Reverse of the number=10b+a

a+b=9(given)-------(i)

10b+a=10a+b+27

$= > 9b + 9a = 27 \\ \\ b - a = 3( - - - ii)$

Solving equations i and ii we get,

$a = 3 \: \: and \: b = 6$

Therefore original number =36 and reversed number=63