Sum of a digit of the two digit number is 5. When we interchange the digit, it is found that the reasulting new number is less than then the original number by 27. What is the two digit number?
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Let the number be 10x+y
x+y = 5 …(1)
10x+y-(10y+x) = 27, or
10x-x-10y+y= 27, or
9x-9y = 27, or
x-y = 3 …(2)
Add (1) and (2)
2x= 8, or
x = 4 and y = 1
So the number is 41 and its subsidiary is 14 and the difference between them is 27 and the sum of the digits is 5.
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