Question

Sum of a digits of a 2 digit number is 9 when we interchange the digit the resulting new number is greater than the original number by 27. What is the 2 digit number​

Answer 1

Let the digit at units place be x.

Then,the digit in tens place = (9-x)

original number= 10*(9-x)+x

=90-10x+x

=90-9x

On reversing the digits ,

10*x+(9-x)

=9x+9

Now,

(Original number)-(New number)=27

or,(90-9x)-(9x+9)=27

or,90-9x-9x-9=27

or,81-18x=27

or,18x=81-27

or,18x=54

or,x=54/18

or,x=3

Now,

Original number=(90-9x)

=90-9*3

=90-27

=63

New number=9x+9

= 9*3+9

=27+9

=36

Hope this may help you!!