sum of a number and the reciprocal and three times the number is 37/3 find the number
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Answered by
2
Answer:
x + 3/x = -4
x² + 3 = -4x
x² + 4x + 3 = 0
(x + 1) (x + 3) = 0
x = -1 or x = -3
check: (-1) + (3/-1) = -1 - 3 = -4
(-3) + (3/(-3)) = -3 -1 = 14
Answered by
1
Answer:
x = 3
Step-by-step explanation:
let number be x
as per the given statement
x + 1/x + 3x = 37/3
4x + 1/x = 37/3
4 x^2 + 1 = 37x/3 [ multiply both sides by x]
12x^2 + 3 = 37x [ multiply both sides by 3]
12x^2 - 37x + 3 = 0
12x^2 - 36x - x +3 = 0 [ by splitting the middle term]
12x(x - 3) - 1(x - 3) = 0
(12x - 1) ( x - 3) = 0
12x - 1 = 0 or x - 3 = 0
x= 1/12 or x = 3
x= 3 is the number
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