Math, asked by kavya142005, 9 months ago

sum of a number and the reciprocal and three times the number is 37/3 find the number ​

Answers

Answered by SwaggerGabru
2

Answer:

x + 3/x = -4

x² + 3 = -4x

x² + 4x + 3 = 0

(x + 1) (x + 3) = 0

x = -1 or x = -3

check: (-1) + (3/-1) = -1 - 3 = -4

(-3) + (3/(-3)) = -3 -1 = 14

Answered by nprakash28
1

Answer:

x = 3

Step-by-step explanation:

let number be x

as per the given statement

x + 1/x + 3x = 37/3

4x + 1/x = 37/3

4 x^2 + 1 = 37x/3     [ multiply both sides by x]

12x^2 + 3 = 37x     [ multiply both sides by 3]

12x^2 - 37x + 3 = 0

12x^2 - 36x - x +3 = 0     [ by splitting the middle term]

12x(x - 3) - 1(x - 3) = 0

(12x - 1) ( x - 3) = 0

12x - 1 = 0 or x - 3 = 0

x= 1/12 or x = 3

x= 3 is the number

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