Sum of a rational and irrational numbers are always an irrational number.
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Answered by
3
heya......
Let rational number + irrational number = rational number
And we know " rational number can be expressed in the form of pq , where p , q are any integers And q 0 ,
So, we can expressed our assumption As :
pq + x = ab ( Here x is a irrational number )
x = ab - pq So,
x is a rational number , but that contradict our starting assumption .
Hence
rational number + irrational number = irrational number ( hence proved )
tysm...#gozmit
Let rational number + irrational number = rational number
And we know " rational number can be expressed in the form of pq , where p , q are any integers And q 0 ,
So, we can expressed our assumption As :
pq + x = ab ( Here x is a irrational number )
x = ab - pq So,
x is a rational number , but that contradict our starting assumption .
Hence
rational number + irrational number = irrational number ( hence proved )
tysm...#gozmit
Answered by
3
Hey mate!
Here's your answer!!
Let rational number + irrational number = rational number
And we know " rational number can be expressed in the form of p/q , where p , q are any integers And q ≠ 0 ,
So, we can expressed our assumption as :
pq + x = ab
(Here x is a irrational number)
∴x = ab - pq
So,
x is a rational number, but that contradict our starting assumption .
∴ Rational number + irrational number
= irrational number
( hence proved )
✌ ✌ ✌
#BE BRAINLY
Here's your answer!!
Let rational number + irrational number = rational number
And we know " rational number can be expressed in the form of p/q , where p , q are any integers And q ≠ 0 ,
So, we can expressed our assumption as :
pq + x = ab
(Here x is a irrational number)
∴x = ab - pq
So,
x is a rational number, but that contradict our starting assumption .
∴ Rational number + irrational number
= irrational number
( hence proved )
✌ ✌ ✌
#BE BRAINLY
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