Question

sum of a two digit number and the number obtained by reversing the order of digits is 99 find the number if the digits differ by 3

Answer 1

Answer:

Let the 2 digits be x,y. respectively

2 digit number =10x+y

2 digit number obtained by ususing the digit =10y+x

∴10x+y+10y+x=99

⇒11x+11y=99

⇒x+y=9

x−y=3

On adding : 2x=12

x=6

putting x in ⟶(i)

6+y=9

y=3

∴ Number =10x+y=63

or , 10y+x=36.

Answer 2

Step-by-step explanation:

Let the 2 digits be x,y. respectively

2 digit number =10x+y

2 digit number obtained by ususing the digit =10y+x

∴10x+y+10y+x=99

⇒11x+11y=99

⇒x+y=9

x−y=3

On adding : 2x=12

x=6

putting x in ⟶(i)

6+y=9

y=3

∴ Number =10x+y=63

or , 10y+x=36.

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