sum of a two digit number is 12 if the digit at units place is 3 less than two times of the digit at the ten's place, find the number
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Step-by-step explanation:
Let the unit place digit =x
Ten's place digit =12−x
Original number = 10×(12−x)+x
=120−10x+x
=120−9x
Reversing the digit:
Unit digit =12−x
Ten's digit =x
New number formed = 10×x+12−x
=9x+12
As new number is less than the original number by 18
New number = original number −18
9x+12=120−9x−18
18x=120−30
18x=90
x=5
Original number =120−9x
=120−9×5
=120−45
=75
Original number =75.
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