Question

sum of a two digit number is 12 if the digit at units place is 3 less than two times of the digit at the ten's place, find the number​

Answer 1

Step-by-step explanation:

Let the unit place digit =x

Ten's place digit =12−x

Original number = 10×(12−x)+x

=120−10x+x

=120−9x

Reversing the digit:

Unit digit =12−x

Ten's digit =x

New number formed = 10×x+12−x

=9x+12

As new number is less than the original number by 18

New number = original number −18

9x+12=120−9x−18

18x=120−30

18x=90

x=5

Original number =120−9x

=120−9×5

=120−45

=75

Original number =75.