Question

Sum of a two digit number is 9. When the digits are interchanged, it is found the

resulting new number is 27 more than the original number. Find the two digit number.​

Answer 1

Answer:

Hey friend,

Here is the answer you are searching for,

Let the digits be x,y

Given,

x+y = 9

=> y = 9-x

Let the original number be (10y + x),

New number be (10x + y),

Also given,

(10y + x) + 27 = (10x + y)

By taking y as (9-x),

=> 10(9-x)+x+27 = 10x+9-x

=> 90-10x+x+27 = 9x+9

=> 117-9x = 9x+9

=> 18x = 108

=> x = 108/18 = 6

=> y = 9-6 = 3

Therefore,

Digits = 3,6

=> Original number = 36

HOPE IT HELPS YOU.

PLEASE MARK AS BRAINLIEST...

Answer 2

Answer:

Let the number on unit place be x and the number on 10 's place be y

By condition Sum of a two digit number is 9

x+y=9.............(1)

By another condition resulting new number is 27 more than the original number.

Here 10y is interchanged and then it becomes 10x

10x+y=10y+x+27

10x-x=10y-y+27

9x=9y+27

9x-9y=27(multiply the equation by 9)

x-y=27............(2)

Eqn(1)+Eqn(2)

x + y = 9

x - y = 27

_________

2x=36

x=36/2

x=18(Put in eqn I)

x+y=9

18+y=9

y=(-9)

Hope it is correct