Sum of a two digit number is 9 when we interchange the numbers the resulting new number is greater the original number by 45
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ANSWER:
THE NUMBER IS 10(2) + 7 = 20 +7 = 27
ASSUMPTION
Let the number in unit place be y and the number in tenth place in y.
Hence the number be 10x + y
GIVEN:
x + y = 9------->A
10y + x = 45 + 10x + y
9x - 9y + 45 = 0
DIVIDE BY 9 ON BOTH SIDES
x - y = - 5--------->B
ADD A AND B
2x = 4
x = 2
SUBSTITUTE x = 2 in A
2 + y = 9
y = 7
THE NUMBER IS 10(2) + 7 = 20 +7 = 27
VERIFICATION:
THE INTERCHANGED NUMBER
10(7) + 2 = 72
72 - 27 = 45
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