Sum of a two digits number and the number obtained by interchanging the digits is 44. What is the sum of the digits of the number?
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the sum of the digits of the number =4
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let x be the tens digit and y be the ones digit
then, original number= 10x+y(10*x+1*y)
number obtained by inter changing the digits=10y+x
given, sum of two digit number and the number obtained by inter changing the digits=44
i.e 10x+y+10y+x=44
11x+11y=44
11(x+y)=44
x+y=4
therefore, sum of the digits of the number =4
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