Question

Sum of, a2 – b + ab,   b + c – bc and c – a2 – ac   is​

Answer 1

Given:

a² - b + ab

b + c - bc

c - a² - ac

What To Do:

We have to find the sum of the given expression.

Solution:

(a² - b + ab) + (b + c - bc) + (c - a² - ac)

Remove the brackets,

⇒ a² - b + ab + b + c - bc + c - a² - ac

Rearrange the like term,

⇒ a² - a² - b + b + c + c + ab - bc - ac

Solve the 1st like term,

⇒ 0 - b + b + c + c + ab - bc - ac

Solve the 2nd like term,

⇒ 0 + 0 + c + c + ab - bc - ac

Solve the 3rd like term,

⇒ 0 + 0 + 2c + ab - bc - ac

Also written as,

⇒ 2c + ab - bc - ac

∴ Hence, the sum is 2c + ab - bc - ac.

Answer 2

Given:

a² - b + ab

b + c - bc

c - a² - ac

What To Do:

We have to find the sum of the given expression.

Solution:

(a² - b + ab) + (b + c - bc) + (c - a² - ac)

Remove the brackets,

⇒ a² - b + ab + b + c - bc + c - a² - ac

Rearrange the like term,

⇒ a² - a² - b + b + c + c + ab - bc - ac

Solve the 1st like term,

⇒ 0 - b + b + c + c + ab - bc - ac

Solve the 2nd like term,

⇒ 0 + 0 + c + c + ab - bc - ac

Solve the 3rd like term,

⇒ 0 + 0 + 2c + ab - bc - ac

Also written as,

⇒ 2c + ab - bc - ac

∴ Hence, the sum is 2c + ab - bc - ac.