Math, asked by riyank411, 4 months ago

Sum of ages of a and b is 65 years . but b is 5 years more than twice the ages of a

Answers

Answered by ashachawla97
0

Step-by-step explanation:

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Answered by hariompatel642004
0

Step-by-step explanation:

Let the ages of father and his son be x and y respectively.

Case I:- The sum of the ages of father and his son is 65 years.

age of father + age of son = 65

⇒x+y=65⟶(i)

Case II:- After 5 years, fathers age will be twice the age of his son.

Age of father = 2 (age of son)

⇒x+5=2(y+5)

⇒x+5=2y+10

⇒x=2y+5⟶(ii)

From eq

n

(i)&(ii), we have

(2y+5)+y=65

⇒3y=65−5

⇒y=20

Substituting the value of y in eq

n

(i), we have

x+20=65

⇒x=45

Hence, the present age of father and son is 45 and 20 respectively and equation (i)&(ii) are the pair of linear equations in two variables.

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