Question

Sum of ages of a father and the son is 40 years .If fathers age is three times that of his son then
find their present ages.​

Answer 1

Given :-

• Sum of the ages of father and son = 40 years.
• Father's age = 3 times that of his son's age.

To Find :-

• The present ages of father and son.

Solution :-

Let the present age of father be x years and the son be y years.

According to the question,

⇒ x + y = 40.....( 1 )

And,

⇒ x = 3y........( 2 )

Substituting ( 2 ) in ( 1 ) gives,

⇒ 3y + y = 40

⇒ 4y = 40

⇒ y = 40/4

⇒ y = 10

Substituting the value of y in ( 2 ) gives,

⇒ x = 3y = 3 × 10

⇒ x = 30

Hence,

• Age of father = 30 years.
• Age of son = 10 years.

Answer 2

✯✯ QUESTION ✯✯

Sum of ages of a father and the son is 40 years .If fathers age is three times that of his son then

Find their present ages.

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Sum\:of\:Ages=40}$

$\longmapsto\tt{Let\:Son\:Age\:be=x}$

As Given that Father's Age is three times of his son's age...So ,

$\longmapsto\tt{Let\:Father\:Age\:be=3x}$

➥A.T.Q : -

$\longmapsto\tt{x+3x=40}$

$\longmapsto\tt{4x=40}$

$\longmapsto\tt{x=\cancel\dfrac{40}{4}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{x}\orange{=}\purple{10}}}$

➥Now ,

$\longmapsto\tt{Present\:Age\:of\:Son=x}$

$\longmapsto\tt{\small{\boxed{\bold{\bold{\red{\sf{10\:years}}}}}}}$

$\longmapsto\tt{Present\:Age\:of\:Father=3x}$

$\longmapsto\tt{3(10)}$

$\longmapsto\tt{\small{\boxed{\bold{\bold{\green{\sf{30\:years}}}}}}}$