Sum of ages of father and son is 45 years. Five years ago the product of their ages was 124 what is their present ages
Answers
Answered by
0
Let age of father be x
Age of son = 45-x
Given,
( x - 5 ) ( 45 - x - 5 ) = 124
( x - 5 ) ( 40 - x ) = 124
40x - x^2 - 200 + 5x = 124
x^2 - 45x + 324 = 0
x^2 - 36x - 9x + 324 = 0
( x - 36 ) ( x - 9 ) = 0
Case(1):
x = 36
Case(2):
Age of son = 45-x
Given,
( x - 5 ) ( 45 - x - 5 ) = 124
( x - 5 ) ( 40 - x ) = 124
40x - x^2 - 200 + 5x = 124
x^2 - 45x + 324 = 0
x^2 - 36x - 9x + 324 = 0
( x - 36 ) ( x - 9 ) = 0
Case(1):
x = 36
Case(2):
GiridharaPrashad:
x = 9
Similar questions