Sum of ages of father and son is 68 years After 8 years father will b thrice older than son .What is the present sons age ?
Answers
- Sum of ages of father and son is 68 years.
- After 8 years father will be thrice older than son.
- The present age of son.
Let,
⑴ Present of father is x years.
And
⑵ Present age of his son is y years.
★ It is given that, sum of ages of father and son is 68 years.
☛ After 8 years,
➛ Father's age = (x + 8) years
And
➛ His sons age = (y + 8) years
★ It is given that, after 8 years father will be thrice older than his son.
➳ x + 8 = 3y + 24
☛ Putting the value of x from equation (1), we get
➳ 68 - y + 8 = 3y + 24
➳ 3y + y = 76 - 24
➳ 4y = 52
➳ y =
➳ y =
∴ The present age of his son is 13 years.
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☛ Putting the value of y in equation (1), we get
➳ x = 68 - y
➳ x = 68 - 13
➳ x = 55
∴ The present age of father is 55 years.
Given:
- The sum of ages of the father and the son is 68 years. After eight years, father will be thrice as old as his son.
To find:
- Present age of the son.
Solution: Let the present age of father be x years and the son be y years respectively.
A/Q,
- Case : I) The sum of ages of the father and the son is 68 years.
➠ x + y = 68
➠ x = 68 - y ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀—eq(I).
- Case : II) After eight years, father will be thrice as old as his son.
- Father's age = (x + 8) & Son's age = (y + 8)
★ Age of father = 3 × (Age of son) ★
(x + 8) = 3(y + 8)
x + 8 = 3y + 24
x = 3y + 24 - 8
x = 3y + 16⠀⠀—eq(II).
- By using Both equations, (I) & (II).
68 - y = 3y + 16
68 - 16 = 3y + y
52 = 4y
y = 52/4
y = 13 ★
- Substituting the value of 'y' in equation (I).
➠ x = 68 - y ⠀
➠ x = 68 - 13
➠ x = 55 ★
•°• Hence, the present age of son and father are 13 years and 55 years respectively.
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★ VERIFICATION :
- We're given with the sum of the ages of father and son that is 68 years. Let's verify the ages of father and son. Therefore,
➠ (Father's age) + (Son's age) = 68
➠ 55 + 13 = 68
➠ 68 = 68
⠀⠀⠀⠀⠀ Hence Verified!