Question

Sum of ages of father and son is 68 years After 8 years father will b thrice older than son .What is the present sons age ?​

Answer 1

Step-by-step explanation:

Let the son's age be x years

Age of son after 8 years = x+8 years

Since it is mentioned that the father will be thrice older than the son, therefore we need to find the father's age

Father's age = 3(x+8)

= 3x+24 years

Now we shall form an equation, since the sum of their ages are 68

Therefore

(3x+24)+(x+8) = 68

3x+24 + x+8 = 68

4x + 32 = 68

4x = 36

x = 36/9

x = 4

Therefore the present age of the son is 4 years.

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Answer 2

Heya ,

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⇒Let the son's age be x years .

As mentioned :

⇒The age of father will be = 3 (x + 8)

= 3x + 24

⇒The age of son will be = x + 8

Equation needed :

⇒( 3x + 24 ) + ( x + 8 ) = 68 ( sum of their age's )

⇒ 4x + 32 = 68 ( after opening the brackets )

⇒4x = 36

⇒ x = 36 / 9

⇒ x = 4

Hence , the present age of son's is 4 years .

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