Question

Sum of all 2 digits which give remainder 4 when divided by 6

Answer 1

Let alpha be 'n' and beta be 'm'

n +m= -b/a

So, n+m = 1/2 (from equation ).....(1)

nm=c/a

So, nm = -1......(2)

Now to form quadratic equation from 2n and 2m

2n+2m= 2(n+m)

From eq. 1

2(1/2)=2=2n+2m.....(3)

2n.2m=4nm

From eq. 2

4(-1)=-4=2n.2m....(4)

General formula for quadratic equation is

k[x2-(α+β)x+αβ]

So from eq 3 and 4

k[x2-2x-4]