Sum of all 3 digit number which are divisible by 3 but not divisible by 5
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there are many numbers which are divisible by 3 but not divisible by5
ex:-123
351
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The three digit numbers divisible by 3 form an AP with first term 102, last term 999 and common difference 3
So 999=102+(n-1)3
3n = 999-102+3 = 900
So n=300
Sum of all numbers= 300/2(102+999)
= 1,65,150
But this sequence also has some numbers which are multiples of 5 . These numbers will be multiples of 15 as the lcm of 3 and 5 is 15.
So these numbers also form an AP with first term 105, last term 990 and common difference 15
990=105+(n-1)15
15n = 990 -105+15=900
n=60
So sum = 60/2(105+990) = 32,850
So the required sum= 1,65,150 - 32,850
= 1,32,300
Hope it helps... Mark it as brainliest...
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