sum of all 3digit natural number which are divisible by 7
Answers
Answered by
13
Hey user !!
Here is your answer !!
♦______________________________________________♦
List of three digit numbers divisible by 7 are 105,112.....994
It's clear that the above numbers are in AP
Hence a=105
d=7
an=994
Applying the formula
a + (n-1) d= 994
105 + (n-1) 7= 994
105+7n-7=994
98+7n=994
n=128
Now,
Sn=n/2(2a+(n-1)d)
Sn=128/2 ((2(105)+(128-1)7))
Sn=64(1099)=70336
Hope it is satisfactory :-)
♦____________________________________________♦
Here is your answer !!
♦______________________________________________♦
List of three digit numbers divisible by 7 are 105,112.....994
It's clear that the above numbers are in AP
Hence a=105
d=7
an=994
Applying the formula
a + (n-1) d= 994
105 + (n-1) 7= 994
105+7n-7=994
98+7n=994
n=128
Now,
Sn=n/2(2a+(n-1)d)
Sn=128/2 ((2(105)+(128-1)7))
Sn=64(1099)=70336
Hope it is satisfactory :-)
♦____________________________________________♦
Riyaa11:
hii
Answered by
0
3+5+7=14 which 8s divisible by 7
Similar questions