Sum of all angles of a regular n sided polygon equals two full rotations around onself.
Find each exterior angle of the polygon.
Answers
Answer:
360/n .in this way we can do
Answer:
There are many methods to find the sum of the interior angles of an n-sided convex polygon. Most books discuss only one or two ways.
Method 1
From any one of the vertices, say A 1, construct diagonals to other vertices.
There are altogether (n-2) triangles.
Sum of angles of each triangle = 180°
Sum of interior angles of n-sided polygon
= (n-2) x 180°
Method 2
From any point P on the line segment, say A1 A2, construct lines to the vertices A3, A4, …, An.
There are altogether (n-1) triangles.
Sum of angles of each triangle = 180°
Please note that there is a straight angle
A1PA2 = 180° containing angles which
are not interior angles of the given polygon.
Sum of interior angles of n-sided polygon
= (n-1) x 180°- 180° = (n-2) x 180°
Method 3
From any one point P inside the polygon,
construct lines to the vertices.
There are altogether n triangles.
Sum of angles of each triangle = 180°
Please note that there is an angle at a point = 360° around P containing angles which are not interior angles of the given polygon.
Sum of interior angles of n-sided polygon
= n x 180°- 360° = (n-2) x 180°
360 / N is also a way to find the angle....
HOPE THAT IT WAS HELPFUL!!!!
MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!