Math, asked by pallak3692, 1 year ago

Sum of all even natural numbers less than 85

Answers

Answered by Swastikagarwal
9
The series goes like 2,4,6.....84
Sum is given be
(n (x + y)) \div 2
where n is the total no. of terms and X is the first term whereas y is the last term.

to find no. of terms.
y=X+(n-1)d
where d is difference between adjacent terms
84=2+(n-1)2
82=(n-1)2
n=42

sum = 42(86)/2


solve and u will get the answer. thanks.
Answered by aliyasubeer
0

Answer:

Sum of all even natural numbers less than 85 is 1806.

Step-by-step explanation:

  • Sequence of even natural number=2,4,6,....84
  • First term,a= 2
  • Common difference d= 2
  • a_n}=84
  • Number of terms = n
  • sum of n terms= \frac{n}{2 }(first$  term+last$  term)
  • nth term a_n}=a+(n-1)d

                       a+(n-1)d=84\\2+(n-1)2=84\\n-1=41\\n=42

sum of 42 terms= \frac{n}{2 }(first$  term+last$  term)

                          =\frac{42}{2} (2+84)\\\\=1806

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