Question

sum of all first n natural number is 2,4,.........,2n​

Answer 1

Answer:

Given & To Find:

The sum of first n even numbers,.

_____________________________________________________________

The first even number = 2 (excluding 0)

d = 2,/ ( common difference between 2 even numbers)

We know that,

S_n= \frac{n}{2}(2a + (n-1)d)Sn=2n(2a+(n−1)d)

Substituting the known values,

We get,

=> S_n = \frac{n}{2}(2(2)+ (n-1)(2))Sn=2n(2(2)+(n−1)(2))

=> S_n= \frac{n}{2}(2(2 + (n-1)))Sn=2n(2(2+(n−1)))

=> S_n = n (2 + n-1)Sn=n(2+n−1)

=> ∴ S_n = n (n+1) =n^2 +nSn=n(n+1)=n2+n

Step-by-step explanation:

thankyou for the question BE HAPPY #BE HAPPY