sum of all interior angles of a pentagon tell me full sum
Answers
Answer:
Sum of all the interior angles of a polygon = (n – 2)π, where n is the number of side in the polygon.
Step-by-step explanation:
Now, we have to find the sum of the interior angles of a pentagon.
We know that the sum of interior angles ‘A’ of any polygon of sides ‘n’ is given by the formula
A=(n−2)×180∘
Thus, we will use this formula to find the required sum.
We know that a pentagon has 5 sides. Thus,
n=5n=5.
Putting the value of ‘n’ in the formula, we get
A=(n−2)×180∘
⇒A=(5−2)×180∘
⇒A=3×180∘
⇒A=540∘
Thus, the sum of interior angles of a pentagon is 540∘
Now, let us find out the measure of each angle in a regular pentagon.
We can find it through the following method:
We will divide the sum of the measures of the angles by the number of sides of the polygon.
Sum of the measure of the angles of a pentagon=540∘
No. of sides in a pentagon= 5
Thus, measure of one angle of a regular pentagon is give as:
540∘5⇒108∘
Therefore, the measure of one angle of a regular pentagon is 108°.
We can verify it by multiplying 108° by 5.
108∘×5=540∘
But this can only be calculated if the polygon is regular, i.e. we can only find the measure of one angle of a pentagon if the pentagon is a regular one, i.e., all of its sides are of the equal length.
Thus, the required answer is 540∘