sum of all natural number from 1 to200 divisible by 5 is
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The sum of all natural numbers from 1 to woo divisible by 5 is as under:
Ist term is(a) 5
Last term is(l) 200
common diffrence(d) is 5
number of terms(n) is 40
Using formula :
sum =n÷2 (2(a)+(n-1)d)
=40÷2 (2 (5)+(40-1)5)
=20 (10+195)
=20 (205)
=4100
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