Question

sum of all natural numbers between 101 and 999 which are multiples of 5

Answer 1

hello mate
here's your answer

105,110,115,120,..........,995
a=105 , d=5 , l=995
an=a +(n-1)d
995= 105+(n-1)(5)
890=5(n-1)
178= n-1
n=179
Sn=n/2 * (a+l)
=(179/2)*(105+995)
=(179/2)*1100
=(179)(1100)/2
=(179)(550)
= 98450
therefore the sum of all the natural numbers between 101 & 999 is 98450

hope you got your answer
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