Sum of all numbers between 500 to 1000 which are divisible by 2
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Answer:
THIS IS A SUM WHICH CAN BE SOLVED THROUGH ARITHMETIC PROGRESSION
the first term divisible by 2 between 500 and 1000 is 500 and last term is 1000
AP SERIES WOULD BE
500,502,504,506.......1000
SO
a = 500
d = 2
Tn = 1000
Tn = a+ (n-1)d
1000 = 500 + (n-1)(2)
1000 = 500 +2n - 2
1000 - 498 = 2n
502 = 2n
n = 251
now for sum
Sn = n/2[a + Tn]
= 251/2 [500 + 1000]
= 188250 ANS
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