Math, asked by renumrenukam1982, 1 year ago

Sum of all numbers less than 1000 neither divisible by 2 or 5

Answers

Answered by forevershadin
0

Answer:

200000

Step-by-step explanation:

Numbers divisible by 2 upto 1000 are 2, 4 , 6, ........ 1000.


Sum of all the numbers divisible by 2 upto 1000 = 2 + 4 + 6 + ....... + 1000 = 2 (1 + 2 + 3 + .......... + 500)


[Using: sum of first n natural numbers]




Numbers divisible by 5 upto 1000 are 5, 10 , 15, ........ 1000.


Sum of all the numbers divisible by 5 upto 1000 = 5 + 10 + 15 + ....... + 1000 = 5 (1 + 2 + 3 + ........ + 200)




Let us find out the sum of all the numbers which are divisible by both 5 and 2.




Numbers divisible by both 2 and 5 will be divisible by 10.


The numbers upto 1000 which are divisible by 10 are: 10, 20, 30, 40, ............ 990, 1000.


Clearly, this forms an AP with a = 10, d = 10, an = 1000, where n can be found out as follows:


an = a + (n – 1) d


⇒ 1000 = 10 + (n – 1) × 10


⇒n = 100






Sum of all the numbers upto 1000 = 1 + 2 + 3 + ........... + 999 + 1000




Sum of all the numbers less than 1000, which are neither divisible by 5 nor by 2 =


Sum of all the numbers upto 1000 – (Sum of all the numbers divisible by 2 upto 1000 + Sum of all the numbers divisible by 5 upto 1000 – Sum of all the numbers which are divisible by both 2 and 5)


= 500500 – (250500 + 100500 – 50500)


= 200000



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