Question

sum of all odd numbers between 11 to 30 is?​

Answer 1

$\huge\sf\underline\red{➪ANSWER=410}$

$\sf\underline\blue{✩SEE \: \: \: THE \: \: \: ATTACHMENT✔︎}$

Answer 2

$\huge \bf \underline{ \underline\color{pink}Answer}$

Let the 1st term be 'a' = 11

No. Of terms (n) = 20

Common Difference (d) = 1

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Therefore sum of all the numbers in Arithmetic Progression from 11 to 30 are,

$= \frac{n}{2} (2a + (n - 1)d) \\ = \frac{20}{2} (2 \times 11 + (20 - 1)1) \\ = 10(22 + 19) \\ = 10(41) \\ = 410$

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$\mathtt{410\ is \ the \ required \ answer}$