sum of all positive integers from 1 to 821. Pease include explanation and work. I will reward the correct answer.
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Answer:
337431
Step-by-step explanation:
first term = a = 1
last term = l = 821
common difference = d = 1
l = a+(n-1)d = 821
1+(n-1)1 = 821
n-1 = 820
n = 821
sum = n/2 x (a+l)
= 821/2 x 822 = 821x 411 = 337431
(I have used Arithmetic Progression here to solve the sum)
hope it helps :)
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