Math, asked by devadiksu, 7 months ago

Sum of all real solutions of the equation , log₈ x + log₈ (x - 4) + log₈ (x - 6) = 2 (a) 8 (b) 0 (c) 64 (d) None

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Answered by deviaparnaboddeti
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Step-by-step explanation:

Sum of all real solutions of the equation , log₈ x + log₈ (x - 4) + log₈ (x - 6) = 2 (a) 8 (b) 0 (c) 64 (d) None

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