sum of all the numbers between 1to 100
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Answer:
A=1, d=1, n=100
Sn=n/2(2a+(n-1)d)
S100=50(2+99)
=50(101)
=5050
Sum of all no.s from 1 to 100 is 5050
Hope it helps u....^_^
vishalmarthi:
Thanks
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