Question

Sum of all those numbers between 199 and 900 each of these divided by 16 leaves remainder 9

Answer 1

Answer:

23980

Step-by-step explanation:

Sum of all those numbers between 199 and 900 each of these divided by 16 leaves remainder 9

As number when divided by 16 leaves remainder 9

so number = 16n + 9

16n + 9 > 199

=> 16n > 190

=> n > 11.875

=> n ≥ 12

16n + 9 < 900

=> 16n < 891

=> n < 55.6875

=> n ≤ 55

12≤ n ≤ 55

201  ,  217  , 233 ,................................... , 873 , 889

number of terms = 44

This is an AP  where

first term = 201

Last term = 889

number of terms = 44

Sum = (number of terms/2) ( First Term + Last Term)

= (44/2)(201 + 889)

= 22 * 1090

= 23980