Math, asked by msg18, 1 year ago

sum of all three digit natural numbers which are divisible by 9

Answers

Answered by manasiriya2003
7

Answer:

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Answered by samar12310
4
Three digit natural number which are divisible by 9 are 108,117-------999.

here,a=108

d=9

and l=999

l=a+(n-1)d

999=108+(n-1)9

999-108=(n-1)9

891=(n-1)9

n-1=891÷9

n-1=99

n=100

then,.

Sn=n/2{2a+(n-1)d}

=100/2{2×108+(100-1)9}

=50{216+891)

=55350 Ans
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