sum of all three digit natural numbers which are divisible by 9
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Three digit natural number which are divisible by 9 are 108,117-------999.
here,a=108
d=9
and l=999
l=a+(n-1)d
999=108+(n-1)9
999-108=(n-1)9
891=(n-1)9
n-1=891÷9
n-1=99
n=100
then,.
Sn=n/2{2a+(n-1)d}
=100/2{2×108+(100-1)9}
=50{216+891)
=55350 Ans
here,a=108
d=9
and l=999
l=a+(n-1)d
999=108+(n-1)9
999-108=(n-1)9
891=(n-1)9
n-1=891÷9
n-1=99
n=100
then,.
Sn=n/2{2a+(n-1)d}
=100/2{2×108+(100-1)9}
=50{216+891)
=55350 Ans
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