Math, asked by Aviral8914, 1 year ago

Sum of all three digits number leaves remainder 3 when divided by 5

Answers

Answered by rohan568
0

this will be the answer for the following

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Answered by keshav012345
0

smallest 3 digit number which leave the remainder 3 when divided by 5 =103

largest 3 digit number which leave the remainder 3 when divided by 5 =998

3 digit number after 103 which leave the remainder 3 when divided by 5 =108

an ap is formed: 103,108........998

first term=103

common difference=5

let the total no. of three digit numbers which leave the remainder 3 when divided by 5=n

998=103+(n-1)5

180=n

sum of ap=180/2 *(103+998)=90*1101

=99090

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