Question

Sum of all zeroes of (y+2)(y-3)(y^2-1) is

Answer 1

Answer:

$zero \: is \: = > \\ \\ y = - 2 \\ y = 3 \\ y = 1 \\ y = - 1 \\ \\ sum = - 2 + 3 + 1 - 1 = 1$